PoE power budget calculator
Work out how much of an 802.3af / 802.3at / 802.3bt port budget actually reaches the powered device after the cable's I²R loss — and the longest run that still delivers your target power.
PSE & cable
PSE standard
Port budget at a nominal 48 V PSE supply.
Cable
Single-conductor resistance per metre.
One-way run, m
Pair mode
Auto — 802.3af/at drive 2 pairs, 802.3bt drives 4 (loop resistance halved).
Fill to get the max cable length that still delivers it
- Port current (I)
- 0.625A
- Loop resistance (R_loop)
- 8.4Ω
- Cable loss
- 3.28W
- Power at PD
- 26.72W
- Voltage at PD
- 42.8V
- Cable loss
- 10.9%
- Max length for target power
- --m
About the budget
The port budget is the maximum the PSE can source, not what the PD consumes. A PD only draws the power its class requests — classes are lower than the port maximum — so a real installation budgets against the PD class power and adds a derating margin for ambient temperature, in-line splitters and legacy equipment. Long runs also cap the budget through voltage, not just power: the 802.3bt Type 4 budget pulls 1.875 A, and over 100 m of 24 AWG solid the voltage at the PD falls to about 40 V — the standard is designed to keep a Type 4 link powered across the full 100 m.
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Frequently asked questions
How is the power at the powered device (PD) calculated?
The port current is I = P_pse / 48, and the loop resistance is R_loop = R_single·length for 2-pair mode (the source and return legs each run over one twisted pair, two conductors in parallel) or R_single/2·length for 4-pair. The cable loss is I²·R_loop. Power at the PD is the port budget minus the cable loss, and the voltage at the PD is 48 − I·R_loop. For 802.3at (30 W) over 100 m of 24 AWG solid cable this gives 0.625 A, 8.4 Ω, 3.28 W of loss and about 26.7 W at 42.8 V at the device.
What is the maximum cable length for a 30 W 802.3at port?
The theoretical limit is the length at which the cable loss eats the entire budget, but the practical limit is much shorter because the PD still needs a working voltage. With a 26.72 W target on 24 AWG solid cable the tool resolves back to 100 m; pushing the target higher shrinks the allowable run. Real budgets are set by PD class power and derating, not the raw port rating.
Why does 802.3bt give a lower voltage drop per metre than 802.3af?
802.3bt uses all four pairs in parallel instead of just two, which halves the loop resistance the current travels through. Although the port current rises (up to 1.875 A for Type 4), the reduced loop resistance means the volt-drop per metre stays comparable — which is exactly how 60 W and 90 W budgets survive a 100 m cable.
Should I budget against the PSE port rating or the PD class?
Always budget against the PD class power, which is lower than the port maximum — an 802.3at switch port can source 30 W but a Class 3 PD only draws about 13 W. The port rating sets the headroom of the budget; the class power sets what the cable actually carries. Add derating for ambient temperature, splitters and legacy equipment on top.
Worked example
Take an 802.3at port (30 W) driving 100 m of 24 AWG solid cable in 2-pair mode. Loop resistance is 0.084 × 100 = 8.4 Ω (two conductors in parallel per leg). The port current is 30 / 48 = 0.625 A, so the cable loss is 0.625² × 8.4 = 3.28 W. That leaves 26.72 W at the PD, at 48 − 0.625 × 8.4 = 42.8 V — about 11% of the port budget lost to the cable. On the same cable an 802.3af port (15.4 W) draws 0.3208 A, loses only 0.86 W and delivers 14.54 W.
Use the reverse mode to ask the question the other way: if the PD needs 26.72 W, the max run is (30 − 26.72) / (0.625² × 0.084) ≈ 100 m. IC Source Direct provides this tool for reference only.
Related calculators
Pair the PoE budget with the voltage drop, cable current, twisted pair impedance and coax attenuation calculators for the full signal-and-power pass on a run.
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